Tuesday, July 28, 2009
Friday, July 17, 2009
problem on simple interest
Topic:- simple interest
Interest is a fee paid on borrowed assets. It is the price paid for the use of borrowed money or, money earned by deposited funds. Assets that are sometimes lent with interest include money, shares, consumer goods through hire purchase, major assets such as aircraft, and even entire factories in finance lease arrangements.
Let's see a problem on this.
Question:
Greg invests $1200 at an annual rate of 6.5%. How long will it take until Greg earns $195 in interest?
Solution:
Formula to find the interest is
Interest is a fee paid on borrowed assets. It is the price paid for the use of borrowed money or, money earned by deposited funds. Assets that are sometimes lent with interest include money, shares, consumer goods through hire purchase, major assets such as aircraft, and even entire factories in finance lease arrangements.
Let's see a problem on this.
Question:
Greg invests $1200 at an annual rate of 6.5%. How long will it take until Greg earns $195 in interest?
Solution:
Formula to find the interest is
For more help on this ,you can reply me.
I = PTR/100
here p = profit=1200
t = time
r = rate=6.5
Substitute the values in formula,so that
(1200 x T x 6.5)
195 = -----------------
100
T = 2.4
Greg will earn $195 in interest in 2.5 years.
Monday, July 6, 2009
additoin of exponentials
Topic:- exponentials
Let's see what is exponent first, generally
This math help gives a example problem on addition of exponents.
Question:-
Let's see what is exponent first, generally
BaseExponent | The exponent tells us how many times the base is used as a factor. |
For example, to write 2 as a factor one million times, the base is 2, and the exponent is 1,000,000. We write this number in exponential form as follows:
2 | 1,000,000 | read as two raised to the millionth power |
This math help gives a example problem on addition of exponents.
Question:-
For more help on this, you can reply me.
-3 z6(b3y2z2)
Answer:-
-3 z6(b3y2z2)
Here we have 'z' for twice ,
So we can put them as 1 term by
additing the exponentials
we can add them by using exponent rule
formula of exponent
am * a n = a m+n
So,
-3 (z6+2*b3*y2)
-3 (z8*b3*y2)
-3z6+2*b3*y2 is the Answer
Thursday, June 18, 2009
Topic:Probability
Probability, is a way of expressing knowledge or belief that an event will occur or has occurred.Here is some probability problems ,which help you to understand the concept much better.
Questions & Answers
1- Mr. Johnson taught a music class for 25 students under the age of ten. He randomlychose one of them. What was the probability that the student was under twelve?Ans:-
The probability that the student was under twelve was 25/25, so P = 1.2- The compact disk Jane bought had 12 songs. The first four were rock music. Tracks
number 5 through 12 were ballads. She selected the random function in her Compact
Disk Player. What is the probability of first listening to a balla?
Ans:-
The probability of listening to a ballad is 8/12, so P = 0.67.
I hope it helped you ,for more math help ,you can reply me.
Thursday, May 21, 2009
Problem on Solving a Function and Show Graphical Representation for the Function
Relations and functions are the dependent concepts of math where the value of a variable is dependent on the other variable in the given function. It is expressed in terms of graphical representation as shown in the below example
Topic : Solving a Function and expressing graphically
In the given function variable 'x' is the independent value and y is the dependent one.
Problem : a) If y = √x −1, Find the values for x = 0, 1, 2, 3, 4.Round to three decimal places where necessary.
b) Explain why no negative values are chosen as values to substitute
in for x.
c) Draw a graphical representation for the values.
(a)Solution :
When x = 0
y = √x – 1
= √0 – 1
= 0 – 1
= -1
When x = 1
y = √x – 1
= √1 – 1
= 1 – 1 and y = -1 - 1
= 0 and y = -2
When x = 2
y = √x – 1
= √2 – 1
= 1.414 – 1 and y = -1.414 - 1
= 0.414 and y = -2.414
When x = 3
y = √x – 1
= √3 – 1
= 1.732 – 1 and y = -1.732 - 1
= 0.732 and y = -2.732
When x = 4
y = √x – 1
= √4 – 1
= 2 – 1 and y = -2 - 1
= 1 and y = -3
(b) Solution :
No negative values are chosen for x because square root of a negative
number is imaginary and is not defined in real space.
(c) Solution :
Topic : Solving a Function and expressing graphically
In the given function variable 'x' is the independent value and y is the dependent one.
Problem : a) If y = √x −1, Find the values for x = 0, 1, 2, 3, 4.Round to three decimal places where necessary.
b) Explain why no negative values are chosen as values to substitute
in for x.
c) Draw a graphical representation for the values.
(a)Solution :
When x = 0
y = √x – 1
= √0 – 1
= 0 – 1
= -1
When x = 1
y = √x – 1
= √1 – 1
= 1 – 1 and y = -1 - 1
= 0 and y = -2
When x = 2
y = √x – 1
= √2 – 1
= 1.414 – 1 and y = -1.414 - 1
= 0.414 and y = -2.414
When x = 3
y = √x – 1
= √3 – 1
= 1.732 – 1 and y = -1.732 - 1
= 0.732 and y = -2.732
When x = 4
y = √x – 1
= √4 – 1
= 2 – 1 and y = -2 - 1
= 1 and y = -3
(b) Solution :
No negative values are chosen for x because square root of a negative
number is imaginary and is not defined in real space.
(c) Solution :
For more help contact geometry help or algebra help.
Wednesday, May 6, 2009
A Question on Rightangle Triangle and Find length of a Side
On a Right angled triangle, number of theorem are derived. One such theorem is Mid point Theorem, with below example theorem is very well explained.
Topic : Right angle Triangle and Mid Point Theorem
Problem : Given angle C is a right angle, E is a midpoint of AC, F is the midpoint of BC, AF = √41, BE = 2√26, Find AB
Solution :
From the figure,
In ∆ACF
AC2 + CF2 = AF2 (by Pythagoras Theorem)
AC2 + (CB/2)2 = (√41)2 (as CF is half of CB)
AC2 + CB2/4 = 41
Now in ∆ECB
EC2 + CB2 = EB2
(AC/2)2 + CB2 = (2√26)2 (as EC is half of AC)
AC2/4 + CB2 = 104
Now adding both the equations, we get
AC2 + CB2/4 + AC2/4 + CB2 = 41 + 104
(1+1/4)AC2 + (1+1/4)CB2 = 145
5AC2/4 + 5CB2/4 = 145
5/4(AC2 + CB2) = 145
Now, in ∆ACB, AC2 + CB2 = AB2
So we get, 5/4 AB2 = 145
AB2 = 145 * 4/5
AB2 = 116
AB = √116
AB = 2√29
Hope the above elaborated explanation will help you to understand mid point theorem and help you to solve similar kind of problems.
If you have any queries please write to us and geometry help will respond to your queries.
Topic : Right angle Triangle and Mid Point Theorem
Problem : Given angle C is a right angle, E is a midpoint of AC, F is the midpoint of BC, AF = √41, BE = 2√26, Find AB
Solution :
From the figure,
In ∆ACF
AC2 + CF2 = AF2 (by Pythagoras Theorem)
AC2 + (CB/2)2 = (√41)2 (as CF is half of CB)
AC2 + CB2/4 = 41
Now in ∆ECB
EC2 + CB2 = EB2
(AC/2)2 + CB2 = (2√26)2 (as EC is half of AC)
AC2/4 + CB2 = 104
Now adding both the equations, we get
AC2 + CB2/4 + AC2/4 + CB2 = 41 + 104
(1+1/4)AC2 + (1+1/4)CB2 = 145
5AC2/4 + 5CB2/4 = 145
5/4(AC2 + CB2) = 145
Now, in ∆ACB, AC2 + CB2 = AB2
So we get, 5/4 AB2 = 145
AB2 = 145 * 4/5
AB2 = 116
AB = √116
AB = 2√29
Hope the above elaborated explanation will help you to understand mid point theorem and help you to solve similar kind of problems.
If you have any queries please write to us and geometry help will respond to your queries.
Thursday, April 9, 2009
Question on Listing Polygon Names
Topic : Polygon
Question : List the names of Ploygons
Solution :
Sides ------ Name
n ----------N-gon
3 ----------Triangle
4 ----------Quadrilateral
5 ----------Pentagon
6 ----------Hexagon
7 ----------Heptagon
8 ----------Octagon
10 ---------Decagon
12 ---------Dodecagon
Question : List the names of Ploygons
Solution :
Sides ------ Name
n ----------N-gon
3 ----------Triangle
4 ----------Quadrilateral
5 ----------Pentagon
6 ----------Hexagon
7 ----------Heptagon
8 ----------Octagon
10 ---------Decagon
12 ---------Dodecagon
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